If two samples share no loci typed in common, they are incomparable and will produce missing data in a distance matrix, which could lead to problems with further analyses. This function finds these samples and returns a matrix of how many other samples these are incomparable with.

## Usage

incomp(gid)

## Arguments

gid

a genind or genclone object

## Value

a square matrix with samples that are incomparable

## Examples


data(nancycats)
# These two populations have no samples that are incomparable
incomp(nancycats[pop = c(1, 17)])
#> <0 x 0 matrix>

# If you reduce the number of loci, we find that there are
# incomparable samples.
incomp(nancycats[pop = c(1, 17), loc = c(1, 4)])
#>      N215 N216 N282 N283 N288 N291 N292 N293 N294 N295 N296 N297 N281 N289 N290
#> N215    1    1    0    0    0    0    0    0    0    0    0    0    0    0    0
#> N216    1    1    0    0    0    0    0    0    0    0    0    0    0    0    0
#> N282    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N283    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N288    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N291    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N292    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N293    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N294    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N295    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N296    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N297    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N281    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N289    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1
#> N290    0    0    1    1    1    1    1    1    1    1    1    1    1    1    1